OneStopGate.Com
OnestopGate   OnestopGate
   Sunday, April 28, 2024 Login  
OnestopGate
Home | Overview | Syllabus | Tutorials | FAQs | Downloads | Recommended Websites | Advertise | Payments | Contact Us | Forum
OneStopGate

GATE Resources
Gate Articles
Gate Books
Gate Colleges 
Gate Downloads 
Gate Faqs
Gate Jobs
Gate News 
Gate Sample Papers
Training Institutes

GATE Overview
Overview
GATE Eligibility
Structure Of GATE
GATE Coaching Centers
Colleges Providing M.Tech/M.E.
GATE Score
GATE Results
PG with Scholarships
Article On GATE
Admission Process For M.Tech/ MCP-PhD
GATE Topper 2012-13
GATE Forum




GATE 2025 Exclusive
Organizing Institute
Important Dates
How to Apply
Discipline Codes
GATE 2025 Exam Structure

GATE 2025 Syllabus
Aerospace Engg..
Agricultural Engg..
Architecture and Planning
Chemical Engg..
Chemistry
Civil Engg..
Computer Science / IT
Electronics & Communication Engg..
Electrical Engg..
Engineering Sciences
Geology and Geophysics
Instrumentation Engineering
Life Sciences
Mathematics
Mechanical Engg..
Metallurgical Engg..
Mining Engg..
Physics
Production & Industrial Engg..
Pharmaceutical Sciences
Textile Engineering and Fibre Science

GATE Study Material
Aerospace Engg..
Agricultural Engg..
Chemical Engg..
Chemistry
Civil Engg..
Computer Science / IT
Electronics & Communication Engg..
Electrical Engg..
Engineering Sciences
Instrumentation Engg..
Life Sciences
Mathematics
Mechanical Engg..
Physics
Pharmaceutical Sciences
Textile Engineering  and Fibre Science

GATE Preparation
GATE Pattern
GATE Tips N Tricks
Compare Evaluation
Sample Papers 
Gate Downloads 
Experts View

CEED 2013
CEED Exams
Eligibility
Application Forms
Important Dates
Contact Address
Examination Centres
CEED Sample Papers

Discuss GATE
GATE Forum
Exam Cities
Contact Details
Bank Details

Miscellaneous
Advertisment
Contact Us


Home » Gate Study Material » Mathematics » Partial Differential Equations » Hyperbolic Equations

Hyperbolic Equations

Looking for GATE Preparation Material? Join & Get here now!

** Gate 2013 Question Papers.. ** CEED 2013 Results.. ** Gate 2013 Question Papers With Solutions.. ** GATE 2013 CUT-OFFs.. ** GATE 2013 Results.. **

Hyperbolic Equations

Hyperbolic Equations

The quadratic form, Eq.(6.12), determined by the coefficients $ A$ , $ B$ , and $ C$ of the given p.d.e. can be factored into two ordinary differential equation

$\displaystyle A\,dy = (B+\sqrt{B^2-AC})\,dx~\quad~\textrm{and}~\quad~A\,dy = (B-
\sqrt{B^2-AC})\,dx\,.
$







These are the equations for the two families of characteristic curves of the given p.d.e.

Their significance, we recall, is this: if the boundary line coincides with one of them, then specifying Cauchy data on it will not yield a unique solution. If, however, the boundary line intersects each family only once, then the Cauchy data will yields a unique solution.

This point becomes particularly transparent if one introduces the curvilinear coordinates $ \lambda $ and $ \mu $ relative to which the given p.d.e. assumes its standard form, Eq.(>6.13). We shall consider the hyperbolic case by assuming that

$\displaystyle B^2(x,y)-A(x,y)C(x,y)>0
$

throughout the $ (x,y)$ domain.

We shall demand the new coordinates $ \lambda $ and $ \mu $ - the characteristic coordinates - have the property that their isograms (``loci of points of constant values'') contain the characteristic lines $ (x(s),y(s))$ , i.e.,

$\displaystyle \lambda (x(s),y(s)) =\textrm{const}~\quad~\textrm{and}~\quad~\mu (x(s),y(s))
=\textrm{const}
$

for all $ s$ . This implies that

$\displaystyle \lambda_x\frac{dx}{ds}+\lambda_y\frac{dy}{ds}=0~\quad~\textrm{and}~\quad~
\mu_x\frac{dx}{ds}+\mu_y\frac{dy}{ds}=0
$

where, as usual

$\displaystyle \lambda_x = \frac{\partial\lambda}{\partial x}\,,\textrm{etc.}
$

Substituting these equations into Eq.(6.12), the equation for the characteristic directions, one obtains
 

$\displaystyle A\left(\frac{\partial\lambda}{\partial x}\right)^2+2B\frac{\parti...
...lambda}{\partial y} +C\left(\frac{\partial\lambda}
{\partial y}\right)^2 = 0\,.$     (614)

 

An equation with the same coefficients is obtained for the other function $ \mu (x,y)$ . The two solutions $ \lambda (x,y)$ and $ \mu (x,y)$ are real valued functions. Their isograms, the characteristics of the hyperbolic equation, give us the new curvilinear coordinate system

$\displaystyle \lambda =\lambda (x,y)~~\qquad~~\mu = \mu (x,y)\,.
$

The partial derivatives of the given differential equation are now as follows
$\displaystyle \frac{\partial^2\psi}{\partial x^2}$ $\displaystyle =$ $\displaystyle \frac{\partial^2\psi}{\partial
\lambda^2}(\lambda_x)^2+2\frac{\pa...
...partial\mu}
\lambda_x\mu_x+\frac{\partial^2\psi}{\partial\mu^2}(\mu_x)^2+\cdots$ $\displaystyle \frac{\partial^2\psi}{\partial x\partial y}$ $\displaystyle =$ $\displaystyle \frac{\partial^2\psi}
{\partial\lambda^2}\lambda_x\lambda_y+\frac...
...a_x\mu_y+\mu_x\lambda_y)+\frac{\partial^2\psi}{\partial
\mu^2}\mu_x\mu_y+\cdots$ $\displaystyle \frac{\partial^2\psi}{\partial y^2}$ $\displaystyle =$ $\displaystyle \frac{\partial^2\psi}{\partial
\lambda^2}\lambda^2_y+2\frac{\part...
...tial\mu}
\lambda_y\mu_y +\frac{\partial^2\psi}{\partial\mu^2}\mu^2_y +\cdots\,.$
 

Here $ +\cdots$ refers to additional terms involving only the first partial derivatives of $ \psi $ . Inserting these expressions into the given p.d. equation, one obtains
 

$\displaystyle [A\lambda^2_x+2B\lambda_x\lambda_y+C\lambda^2_y]\frac{\partial^2\psi}
{\partial\lambda^2}$ $\displaystyle +$ $\displaystyle [2A\lambda_x\mu_x+B(\lambda_x\mu_y+\mu_x\lambda_y)+
2C\lambda_y\mu_y]\frac{\partial^2\psi}{\partial\lambda\partial\mu}$ $\displaystyle +$ $\displaystyle [A\mu^2_x+2B\mu_x\mu_y+C\mu^2_y]\frac{\partial^2\psi}{\partial\mu^2}$ $\displaystyle =$ $\displaystyle \Phi '\left(\lambda ,\mu ,\psi ,\frac{\partial\psi}{\partial\lambda}\,,~
\frac{\partial\psi}{\partial\mu}\right)\,.$(615)
It follows from Equation 6.14 that the coefficients of $ \psi_{\lambda\lambda}$ and $ \psi_{\mu\mu}$ vanish. Solving for $ \frac{\partial^2\psi}{\partial\lambda\partial\mu}$ yields Equation > 6.13, the hyperbolic equation in normal form.

The coordinates $ \lambda $ and $ \mu $ , whose surfaces contain the characteristic lines, are called the characteristic coordinates or null coordinates of the hyperbolic equation.

These coordinates are important for at least two reasons. First of all, they are boundaries across which a solution can be nonanalytic. If $ \lambda(x,y)=\lambda_0$ is one of the isograms (``locus of points where $ \lambda $ has constant value'') of the solution to Eq.(6.14), then the first term of the p.d. Eq.(6.15)

$\displaystyle [A\lambda^2_x+2B\lambda_x\lambda_y+C\lambda^2_y]\frac{\partial^2\psi}
{\partial\lambda^2}=finite
$

even if $ \frac{\partial^2\psi}{\partial\lambda^2}\rightarrow\infty$ as $ \lambda\to \lambda_0$ . In other words, there are solutions to Eq.(6.15) for which the first derivative $ \frac{\partial\psi}{\partial\lambda}$ has a discontinuity across the characteristic $ \lambda(x,y)=\lambda_0$ . Similarly, there exist solutions to Eq.(6.15) whose first derivative $ \frac{\partial\psi}{\partial\mu}$ has a discontinuity across $ \mu(x,y)=\mu_0$ whenever $ \mu (x,y)$ satisfies Eq.(6.14) with $ \lambda $ replaced by $ \mu $ .

Secondly, these coordinates depict the history of a moving disturbance. The simple string illustrates the issue involved.


Example: The Simple string The governing equation is

$\displaystyle \frac{\partial^2\psi}{\partial z^2} - \frac{1}{c^2}~\frac{\partial^2\psi}
{\partial t^2} = 0\,.
$

Its characteristic coordinates are the ``retarded'' and the ``advanced'' times

$\displaystyle \lambda =ct-z~\quad~\textrm{and}~\quad~\mu =z+ct
$

and its normal form is

$\displaystyle \frac{\partial^2\psi}{\partial\lambda\partial\mu} = 0\,.
$

The solution is

$\displaystyle \psi = f(\lambda )+g(\mu )
$

where $ f$ and $ g$ are any functions of $ \lambda $ and $ \mu $ .

Next consider the initial value data at $ t=0$ :
 

$\displaystyle \psi_0(z) \equiv \psi (t=0,z)$ $\displaystyle =$ $\displaystyle f(-z)+g(z)~~\qquad~~\qquad~~~~~~\textrm{\lq\lq initial~amplitude''}$ $\displaystyle V_0(z) \equiv \left.\frac{\partial\psi (t,z)}{\partial t}\right\vert _{t=0}$ $\displaystyle =$ $\displaystyle \left.\frac{\partial
\lambda}{\partial t}~\frac{\partial\psi}{\pa...
...al\psi}{\partial\mu}
\right\vert _{\mu =z}~~\qquad\textrm{\lq\lq initial~velocity''}$ $\displaystyle =$ $\displaystyle c f'(-z) +c g'(z)\,.$
These equations imply
 
$\displaystyle f(\lambda )$ $\displaystyle =$ $\displaystyle \frac{1}{2}\psi_0 (-\lambda )+\frac{1}{2c}\int^{-\lambda}_0
V_0(z')dz'$  
$\displaystyle g(\mu )$ $\displaystyle =$ $\displaystyle \frac{1}{2} \psi_0(\mu )+\frac{1}{2c}\int^\mu_0 V_0(z') dz'\,.$  

Consider the intersection of the two families of characteristics with the boundary line $ t=0$ as in the figure below.

\begin{texdraw}
\drawdim cm
\move(0 0)
\lvec(6 0)
\move(3 -1.5)
\lvec(3 3)
\move...
...ove(6.2 0)
\textref h:L v:C
\htext{$z$}
\rmove(.5 0)
\ravec(.75 0)
\end{texdraw}
 
Figure 6.1: Characteristic coordinate lines $ \mu $ and $ \lambda $ as determined by the wave equation for a simple string.
 

Note that $ f$ is constant along the $ \lambda $ characteristics (i.e., where $ \lambda =$ constant), while $ g$ is constant along the $ \mu $ characteristics. It follows that if $ f$ is known on the boundary segment $ RS$ , then $ f$ is known along all the $ \lambda $ -characteristics intersecting $ RS$ . Similarly, if $ g$ is known along $ RS$ , then $ g$ is known along all the $ \mu $ -characteristics intersecting $ RS$ . And this is precisely the case because the Cauchy data on $ RS$ determine the values of both $ f$ and $ g$ on that segment.

Being the sum of the two functions, the solution to the wave equation is
 

$\displaystyle \psi (z,t)$ $\displaystyle =$ $\displaystyle f(ct-z)+g(ct+z)$  
  $\displaystyle =$ $\displaystyle \frac{1}{2}\psi_0(z-ct)+\frac{1}{2}\psi_0(z+ct)+
\frac{1}{2c}\int_{z-ct}^{z+ct}V_0(z')dz'$ (616)

Thus one sees that any disturbance on a string consists of two parts: one propagating to the right the other to the left. The propagation speeds are $ \pm c$ , the slopes of the characteristics relative to the $ t$ -$ z$ coordinate system. The idiosyncratic aspect of the simple string is that these two parts do not change their shape as they propagate along the string.

A general linear hyperbolic system does not share this feature. However, what it does share with a simple string is that its solution is uniquely determined in the common region traversed by the two sets of characteristics which intersect $ RS$ . In fact, the Cauchy data on $ RS$ determine a unique solution $ \psi(z,t)$ at every point in the region $ PRQS$ . This is why it is called the domain of dependence of $ RS$ . To justify these claims it is neccessary to construct this unique solution to a general second order linear hyperbolic differential equation.



Discussion Center

Discuss/
Query

Papers/
Syllabus

Feedback/
Suggestion

Yahoo
Groups

Sirfdosti
Groups

Contact
Us

MEMBERS LOGIN
  
Email ID:
Password:

  Forgot Password?
 New User? Register!

INTERVIEW EBOOK
Get 9,000+ Interview Questions & Answers in an eBook. Interview Question & Answer Guide
  • 9,000+ Interview Questions
  • All Questions Answered
  • 5 FREE Bonuses
  • Free Upgrades
GATE RESOURCES
 
  • Gate Books
  • Training Institutes
  • Gate FAQs
  • GATE BOOKS
     
  • Mechanical Engineeering Books
  • Robotics Automations Engineering Books
  • Civil Engineering Books
  • Chemical Engineering Books
  • Environmental Engineering Books
  • Electrical Engineering Books
  • Electronics Engineering Books
  • Information Technology Books
  • Software Engineering Books
  • GATE Preparation Books
  • Exciting Offers



    GATE Exam, Gate 2009, Gate Papers, Gate Preparation & Related Pages


    GATE Overview | GATE Eligibility | Structure Of GATE | GATE Training Institutes | Colleges Providing M.Tech/M.E. | GATE Score | GATE Results | PG with Scholarships | Article On GATE | GATE Forum | GATE 2009 Exclusive | GATE 2009 Syllabus | GATE Organizing Institute | Important Dates for GATE Exam | How to Apply for GATE | Discipline / Branch Codes | GATE Syllabus for Aerospace Engineering | GATE Syllabus for Agricultural Engineering | GATE Syllabus for Architecture and Planning | GATE Syllabus for Chemical Engineering | GATE Syllabus for Chemistry | GATE Syllabus for Civil Engineering | GATE Syllabus for Computer Science / IT | GATE Syllabus for Electronics and Communication Engineering | GATE Syllabus for Engineering Sciences | GATE Syllabus for Geology and Geophysics | GATE Syllabus for Instrumentation Engineering | GATE Syllabus for Life Sciences | GATE Syllabus for Mathematics | GATE Syllabus for Mechanical Engineering | GATE Syllabus for Metallurgical Engineering | GATE Syllabus for Mining Engineering | GATE Syllabus for Physics | GATE Syllabus for Production and Industrial Engineering | GATE Syllabus for Pharmaceutical Sciences | GATE Syllabus for Textile Engineering and Fibre Science | GATE Preparation | GATE Pattern | GATE Tips & Tricks | GATE Compare Evaluation | GATE Sample Papers | GATE Downloads | Experts View on GATE | CEED 2009 | CEED 2009 Exam | Eligibility for CEED Exam | Application forms of CEED Exam | Important Dates of CEED Exam | Contact Address for CEED Exam | CEED Examination Centres | CEED Sample Papers | Discuss GATE | GATE Forum of OneStopGATE.com | GATE Exam Cities | Contact Details for GATE | Bank Details for GATE | GATE Miscellaneous Info | GATE FAQs | Advertisement on GATE | Contact Us on OneStopGATE |
    Copyright © 2024. One Stop Gate.com. All rights reserved Testimonials |Link To Us |Sitemap |Privacy Policy | Terms and Conditions|About Us
    Our Portals : Academic Tutorials | Best eBooksworld | Beyond Stats | City Details | Interview Questions | India Job Forum | Excellent Mobiles | Free Bangalore | Give Me The Code | Gog Logo | Free Classifieds | Jobs Assist | Interview Questions | One Stop FAQs | One Stop GATE | One Stop GRE | One Stop IAS | One Stop MBA | One Stop SAP | One Stop Testing | Web Hosting | Quick Site Kit | Sirf Dosti | Source Codes World | Tasty Food | Tech Archive | Software Testing Interview Questions | Free Online Exams | The Galz | Top Masala | Vyom | Vyom eBooks | Vyom International | Vyom Links | Vyoms | Vyom World
    C Interview Questions | C++ Interview Questions | Send Free SMS | Placement Papers | SMS Jokes | Cool Forwards | Romantic Shayari