There is a good algorithm that can be stated for how to write the KVL equations
for a loop. We'll need that when we examine this circuit again.
Here's the statement of the algorithm.
Pick a starting point on the
loop you want to write KVL for.
Imagine walking around the loop
- clockwise or counterclockwise.
When you enter an element there
will be a voltage defined across that element. One end will be positive
and the other negative.
Pick the sign of the voltage
definition on the end of the element that you enter. Conversely, you could
choose the sign of the end you leave, except that you have to be consistent all
the way around the loop.
Write down the voltage across
the element using the sign you got in the previous step.
Keep doing that until you have
gone completely around the loop returning to your starting point.
Set your result equal to zero.
Now let's do that for the loops
in the circuit above.
A Comment
Before
we write the KVL equations, we need to notice something. The answer to
Question #7 may not be correct. Let's think a little deeper to be sure we
have it right. We took the correct answer to be two loops. In a
sense that's correct, but in another sense there are three loops. In the
picture below, each of the three buttons - when pressed - will show you one of
the three loops. There's a loop there that you might not have thought
about. Click the three buttons to see the three loops.
Now, let's write KVL for each of the three loops.
For the first loop (Battery,
Element #1, Element #2)
-VB
+ V1 + V2= 0
For the second loop (Element
#2, Element #3, Element #4). Note, you have to be careful with this one
because you might not expect the voltage across Element #3 to be defined the way
it is.
-V2- V3
+ V4 = 0
For the third loop (Battery,
Element #1, Element #3, Element #4)
-VB
+ V1 - V3 + V4 = 0
So, we get three equations - right?
Actually, that's not right, because we do not get three independent equations.
There are only two independent equations we can write.
That's not immediately obvious, so write the three equations as shown below.
We'll put a horizontal line between the first two and the third equation.
-VB
+ V1 + V2 = 0
-V2
- V3 + V4 = 0
-VB
+ V1 - V3 + V4 = 0
Can you see that you can add the first two
equations to get the third? (Actually, there is a -V2
and a +V2, and those are the only things that cancel out when you
add.) The third equation can be obtained from the first two equations, so
it is not an independent equation. When you have the first two equations
you can get the third from them!
What this means is that you have to be careful when you write KVL. You can
write too many equations, and in being careful you might not write enough.
Fortunately, if you look at a circuit you can almost always see how many
independent loops there are by inspection. Going back to our question
about how many loops there are in this circuit, the answer is that there are
three loops but only two independent loops.
Now, let's see if you can apply your knowledge of KVL to solve a few simple
problems.