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Home » GATE Study Material » Electrical Engineering » Digital Signals and Data Representation » D/A Converters

D/A Converters

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D/A Converters

Why Interface Circuits?

Computers don't exist in a vacuum. They have to interface with the world in many ways. You can sit at a keyboard and type and you're using a computer interface. You click a mouse button and that's another interface. Measurement devices often need to communicate with computers also.

  • A motor needs a voltage to run at a certain speed. A computer has to generate than voltage and it will have to be applied to the motor. If the computer calculates the voltage, then A D/A converter can take a digital signal from the computer and generate the required voltage.

There are numerous other situations where you need to have a computer produce a specific voltage for some purpose.


Goals

Here's what you should be able to do after this lesson.

  • Given a D/A converter with a given range and number of bits,

    • To be able to calculate the resolution of the converter.



A Simple Digital To Analog Converter

We are going to start by examining a simple circuit. This circuit is an operational amplifier circuit with three input voltages.

  • Each input voltage is either zero volts or five volts and represents a logical 0 or 1.

  • The input resistors are chosen so that they are not all equal.

  • The resistors are related by: Rc = 2Rb = 4Ra.

To understand how this circuit works we will need to obtain a symbolic expression for the output voltage - one in which we express the output voltage in terms of the binary number that the input represents. We already have an expression for the output voltage.

Vout = (RfVa /Ra) + (RfVb /Rb) + (RfVc /Rc)

We need to interpret this output voltage expression when the inputs represent a binary number.

Let's examine the expression for the output voltage using the relation we required for the resistors.

Rc = 2Rb = 4Ra

Then, the output voltage expression becomes:

Vout = (RfVa /Ra) + (RfVb /Rb) + (RfVc /Rc)

Vout = (RfVa /Ra) + (RfVb /2Ra) + (RfVc /4Ra)

Each input voltage is either zero (0) or five (5) volts, representing either a zero or a one. Although we shouldn't mix Boolean algebra variables and ordinary algebraic variables, we are going to. We're going to say

Va = 5A2

Vb = 5A1

Vc = 5Ao

So

Vout = (Rf/4Ra)(4Va + 2Vb + Vc )

Vout = (5Rf/4Ra)(4A2 + 2A1 + Ao )

And, the question we are left with is "What is (4A2 + 2A1 + Ao )?"

The expression - (4A2 + 2A1 + Ao ) - can be regarded as the binary number represented by A2, A1 and Ao. This table shows the equivalence.

A2

A1

Ao

Binary #

4A2+2A1+Ao

0

0

0

0

0

0

0

1

1

1

0

1

0

2

2

0

1

1

3

3

1

0

0

4

4

1

0

1

5

5

1

1

0

6

6

1

1

1

7

7

In other words, A2 is the 4 bit, A1 is the 2 bit and Ao is the 1 bit.

After all this, we reach these conclusions for this circuit.

  • The inputs can be thought of as a binary number, one that can run from zero (0) to seven (7).

  • The output is a voltage that is proportional to the binary number input.

  • The circuit itself converts a digital representation of a number to an analog version of the same number. The circuit is a digital-to-analog converter also known as a D/A converter.

What if we wanted to convert a digital signal with more bits? The answer to this question should be fairly obvious.

  • More input resistances are needed.

  • The resistances should be chosen in ratios of 2.

  • The LSB has the largest resistance.

  • More significant bits have resistances that decrease by a factor of 2.

Next, we're going to look at some circuits that use the D/A converter.

  • One application of a D/A converter is to convert signals generated within a computer to voltages outside the computer. Examples where this is useful include control systems, where a control signal could be calculated by a computer (implementing some known control algorithm) and then converted to a voltage using a D/A converter. That voltage could end up driving a motor for a pump - among many other things that might occur.

  • D/A converters also occur within larger systems. Shown below is an example.

    • A pulse generator generates a pulse train - a sequence of zeros and ones.

    • The pulse train is counted by a counter.

    • The counter output is the input to the D/A.

    • The D/A output is compared to the voltage input, and when the D/A output exceeds the voltage input, the comparator output changes state and stops the counter.

The second example is really an A/D converter. It's interesting that many A/D converters contain D/A converters within them. D/A converters are often emedded in places where you might not expect to find them. You use them all the time.

You may not think that you have ever used a D/A, but we will convince you that you have. We'll do that by having you use one you have used before.

First, we need a source of digital signals that we can convert to analog signals. The most common source like that is a music CD. Consider what happens when you play a music CD. (Note, we're deliberately emphasizing the phrase music CD because we want to emphasize it is not a CD with program files on it that we want to use.)

  • Your CD has tiny little pits on the surface. You can't really see them, but they are there.

  • A low power laser is flashed on the CD, and the reflectivity is different where there is a pit. That means that the reflected laser signal can be used to read the zeroes and ones on the CD.

  • So, as the CD spins in the holder, a sequences of zeroes and ones is generated and sent on.

  • That sequence of zeroes and ones is converted to an analog voltage that is amplified and fed to an earphone or a speaker.

  • So, you see that you have used an A/D before - if you have ever used a CD player.



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