Fourier Series
Example - Pulse
We are going to examine the Fourier Series for repetitive. The signal we
want to work with is given below in Figure 1.
We will compute the Fourier Series of a general pulse that repeats. The
pulse sequence is shown below. The pulse signal varies between zero volts
and one volt.
Figure 1
Now, to evaluate the
coefficients, we do the integrations indicated above. We have the
following.
or:
an
= 2Asin(nwoTp)/(nTwo)
an
= Asin(nwoTp)/(np)
Similarly,
or:
bn
= 2A[-cos(nwoTp)
+ 1]/(nTwo)
bn
= A[-cos(nwoTp)
+ 1]/(np)
and,
ao
= (Tp/T)
Now, we can compute some of
the coefficients for a particular case. We will examine the situation
where the pulse is high for one-fourth of the period, i.e. when Tp
= T/4. In that situation we have:
nwoTp
= (n2p/T)Tp
= np/2
Note that the a's (the
cosine coefficients) will all be zero for even n's, while the b's (the sine
coefficients) will be zero for every fourth n. That being said, the
coefficients we have computed are given in the table below. For this table
we have assumed a period of 4 seconds.
n
|
an
|
bn
|
0
|
.25
|
-
|
1
|
.31831
|
.31831
|
2
|
0
|
.31831
|
3
|
-.10610
|
.10610
|
4
|
0
|
0
|
5
|
.06366
|
.06366
|
6
|
0
|
.10610
|
7
|
-.04547
|
.04547
|
8
|
0
|
0
|
9
|
.03537
|
.03537 |
10
|
0
|
.06366 |
|