OneStopGate.Com
OnestopGate   OnestopGate
   Tuesday, November 19, 2024 Login  
OnestopGate
Home | Overview | Syllabus | Tutorials | FAQs | Downloads | Recommended Websites | Advertise | Payments | Contact Us | Forum
OneStopGate

GATE Resources
Gate Articles
Gate Books
Gate Colleges 
Gate Downloads 
Gate Faqs
Gate Jobs
Gate News 
Gate Sample Papers
Training Institutes

GATE Overview
Overview
GATE Eligibility
Structure Of GATE
GATE Coaching Centers
Colleges Providing M.Tech/M.E.
GATE Score
GATE Results
PG with Scholarships
Article On GATE
Admission Process For M.Tech/ MCP-PhD
GATE Topper 2012-13
GATE Forum




GATE 2025 Exclusive
Organizing Institute
Important Dates
How to Apply
Discipline Codes
GATE 2025 Exam Structure

GATE 2025 Syllabus
Aerospace Engg..
Agricultural Engg..
Architecture and Planning
Chemical Engg..
Chemistry
Civil Engg..
Computer Science / IT
Electronics & Communication Engg..
Electrical Engg..
Engineering Sciences
Geology and Geophysics
Instrumentation Engineering
Life Sciences
Mathematics
Mechanical Engg..
Metallurgical Engg..
Mining Engg..
Physics
Production & Industrial Engg..
Pharmaceutical Sciences
Textile Engineering and Fibre Science

GATE Study Material
Aerospace Engg..
Agricultural Engg..
Chemical Engg..
Chemistry
Civil Engg..
Computer Science / IT
Electronics & Communication Engg..
Electrical Engg..
Engineering Sciences
Instrumentation Engg..
Life Sciences
Mathematics
Mechanical Engg..
Physics
Pharmaceutical Sciences
Textile Engineering  and Fibre Science

GATE Preparation
GATE Pattern
GATE Tips N Tricks
Compare Evaluation
Sample Papers 
Gate Downloads 
Experts View

CEED 2013
CEED Exams
Eligibility
Application Forms
Important Dates
Contact Address
Examination Centres
CEED Sample Papers

Discuss GATE
GATE Forum
Exam Cities
Contact Details
Bank Details

Miscellaneous
Advertisment
Contact Us


Integers

Looking for GATE Preparation Material? Join & Get here now!

** Gate 2013 Question Papers.. ** CEED 2013 Results.. ** Gate 2013 Question Papers With Solutions.. ** GATE 2013 CUT-OFFs.. ** GATE 2013 Results.. **

Integers

Divisors; prime factorization

The set {..., -2, -1, 0, 1, 2, 3, ...} is called the set of integers, and will be denoted by Z.

1.1.1. Definition. An integer a is called a multiple of an integer b if a=bq for some integer q. In this case we also say that b is a divisor of a, and we use the notation b | a.



In the above case we can also say that b is a factor of a, or that a is divisible by b. If b is not a divisor of a, meaning that a bq for all q Z, then we write b a. The set of all multiples of an integer a will be denoted by

aZ = { m Z | m=aq   for some   q Z }.

1.1.2. Axiom. [Well-Ordering Principle] Every nonempty set of natural numbers contains a smallest element.

1.1.3 Theorem. [Division Algorithm] For any integers a and b, with b>0, there exist unique integers q (the quotient) and r (the remainder) such that a=bq+r, with 0 r<b.

1.1.4. Theorem. Let I be a nonempty set of integers that is closed under addition and subtraction. Then I either consists of zero alone or else contains a smallest positive element, in which case I consists of all multiples of its smallest positive element.

1.1.5. Definition. A positive integer d is called the greatest common divisor of the nonzero integers a and b if

(i) d is a divisor of both a and b,   and

 

(ii) any divisor of both a and b is also a divisor of d.
We will use the notation gcd(a,b), or simply (a,b), for the greatest common divisor of a and b.

1.1.6. Theorem. Any two nonzero integers a and b have a greatest common divisor, which can be expressed as the smallest positive linear combination of a and b.
Moreover, an integer is a linear combination of a and b if and only if it is a multiple of their greatest common divisor.

The greatest common divisor of two numbers can be computed by using a procedure known as the Euclidean algorithm. First, note that if a 0 and b | a, then gcd(a,b) = |b|. The next observation provides the basis for the Euclidean algorithm. If a=bq+r, then (a,b)=(b,r). Thus given integers a>b>0, the Euclidean algorithm uses the division algorithm repeatedly to obtain

a = bq1 + r1,   with 0 r1< b
b = r1q2 + r2,   with 0 r2< r1,
etc.

Since r1 > r2 > . . . , the remainders get smaller and smaller, and after a finite number of steps we obtain a remainder rn+1 = 0. Thus gcd(a,b) = gcd(b,r1) = . . . = rn.

1.2.1. Definition. The nonzero integers a and b are said to be relatively prime if (a,b)=1.

1.2.2 Proposition. Let a,b be nonzero integers. Then (a,b)=1 if and only if there exist integers m,n such that

ma + nb = 1 .

1.2.3 Proposition. Let a,b,c be integers.
(a) If b | ac, then b | (a,b)c.

 

(b) If b | ac and (a,b)=1, then b | c.

 

(c) If b | a, c | a and (b,c)=1, then bc | a.

 

(d) (a,bc)=1 if and only if (a,b)=1 and (a,c)=1.
1.2.4. Definition. An integer p>1 is called a prime number if its only divisors are � 1 and � p. An integer a > 1 is called composite if it is not prime.

1.2.5. Lemma. [Euclid] An integer p>1 is prime if and only if it satisfies the following property: If p | ab for integers a and b, then either p | a or p | b.

1.2.6. Theorem. [Fundamental Theorem of Arithmetic] Any integer a>1 can be factored uniquely as a product of prime numbers, in the form

a = p1m1 p2m2 � � � pnmn

where p1 < p2 < � � � < pn and the exponents m1, m2 , . . . , mn are all positive.

1.2.7. Theorem. [Euclid] There exist infinitely many prime numbers.

1.2.8. Definition. A positive integer m is called the least common multiple of the nonzero integers a and b if

(i) m is a multiple of both a and b,   and

 

(ii) any multiple of both a and b is also a multiple of m.
We will use the notation lcm[a,b] for the least common multiple of a and b.

1.2.9. Proposition. Let a and b be positive integers with prime factorizations

a = p1a1 p2a2 � � � pnan     and     b = p1b1 p2b2 � � � pnbn ,

where ai 0 and bi 0 for all i (allowing use of the same prime factors.)
For each i let di =min { ai, bi } and let mi =max { ai, bi }. Then we have the following factorizations:
(a) gcd(a,b) = p1d1 p2d2 � � � pndn

 

(b) lcm[a,b] = p1m1 p2m2 � � � pnmn

Congruences

1.3.1. Definition. Let n be a positive integer. Integers a and b are said to be congruent modulo n if they have the same remainder when divided by n. This is denoted by writing a b (mod n).

1.3.2. Proposition. Let a,b, and n>0 be integers. Then a b (mod n) if and only if n | (a-b).

When working with congruence modulo n, the integer n is called the modulus. By the preceding proposition, a b (mod n) if and only if a-b=nq for some integer q. We can write this in the form a=b+nq, for some integer q. This observation gives a very useful method of replacing a congruence with an equation (over Z). On the other hand, Proposition 1.3.3 shows that any equation can be converted to a congruence modulo n by simply changing the = sign to . In doing so, any term congruent to 0 can simply be omitted. Thus the equation a=b+nq would be converted back to a b (mod n).

1.3.3 Proposition. Let n>0 be an integer. Then the following conditions hold for all integers a,b,c,d:

(a) If a c (mod n) and b d (mod n), then

then a b c d (mod n), and ab cd (mod n).

(b) If a+c a+d (mod n), then c d (mod n).

If ac ad (mod n) and (a,n)=1, then c d (mod n).

1.3.4. Proposition. Let a and n>1 be integers. There exists an integer b such that ab 1 (mod n) if and only if (a,n)=1.

1.3.5. Theorem. The congruence ax b (mod n) has a solution if and only if b is divisible by d, where d=(a,n).
If d | b, then there are d distinct solutions modulo n, and these solutions are congruent modulo n / d.

1.3.6. Theorem. [Chinese Remainder Theorem] Let n and m be positive integers, with (n,m)=1. Then the system of congruences

x a (mod n)       x b (mod m)

has a solution. Moreover, any two solutions are congruent modulo mn.

1.4.1. Definition. Let a and n>0 be integers. The set of all integers which have the same remainder as a when divided by n is called the congruence class of a modulo n, and is denoted by [a]n, where

[a]n = { x Z | x a (mod n) }.

The collection of all congruence classes modulo n is called the set of integers modulo n, denoted by Zn.

1.4.2 Proposition. Let n be a positive integer, and let a,b be any integers. Then the addition and multiplication of congruence classes given below are well-defined:

[a]n + [b]n = [a+b]n ,       [a]n[b]n = [ab]n.

1.4.3. Definition. If [a]n belongs to Zn, and [a]n[b]n = [0]n for some nonzero congruence class [b]n, then [a]n is called a divisor of zero, modulo n.

1.4.4. Definition. If [a]n belongs to Zn, and [a]n[b]n = [1]n, for some congruence class [b]n, then [b]n is called a multiplicative inverse of [a]n and is denoted by [a]n-1.
In this case, we say that [a]n and [b]n are invertible elements of Zn, or units of Zn.

1.4.5. Proposition. Let n be a positive integer.

(a) The congruence class [a]n has a multiplicative inverse in Zn if and only if (a,n)=1.

 

(b) A nonzero element of Zn either has a multiplicative inverse or is a divisor of zero.
1.4.6. Corollary. The following conditions on the modulus n > 0 are equivalent:
(1) The number n is prime.

 

(2) Zn has no divisors of zero, except [0]n.

 

(3) Every nonzero element of Zn has a multiplicative inverse.
1.4.7. Definition. Let n be a positive integer. The number of positive integers less than or equal to n which are relatively prime to n will be denoted by (n). This function is called Euler's phi-function, or the totient function.

1.4.8. Proposition. If the prime factorization of n is n = p1m1 p2m2 � � � pnmn , then

(n) = n(1-1/p1)(1-1/p2) � � � (1-1/pk).

1.4.9. Definition. The set of units of Zn, the congruence classes [a]n, such that (a,n)=1, will be denoted by
Zn.

The following theorem shows that raising any congruence class in Zn to the power (n) yields the congruence class of 1. It is possible to give a purely number theoretic proof at this point, but in Example 3.2.12 there is a more elegant proof using elementary group theory.

1.4.11. Theorem. [Euler] If (a,n)=1, then a (n) 1 (mod n).

1.4.12 Corollary. [Fermat] If p is prime, then ap a (mod p), for any integer a.



Discussion Center

Discuss/
Query

Papers/
Syllabus

Feedback/
Suggestion

Yahoo
Groups

Sirfdosti
Groups

Contact
Us

MEMBERS LOGIN
  
Email ID:
Password:

  Forgot Password?
 New User? Register!

INTERVIEW EBOOK
Get 9,000+ Interview Questions & Answers in an eBook. Interview Question & Answer Guide
  • 9,000+ Interview Questions
  • All Questions Answered
  • 5 FREE Bonuses
  • Free Upgrades
GATE RESOURCES
 
  • Gate Books
  • Training Institutes
  • Gate FAQs
  • GATE BOOKS
     
  • Mechanical Engineeering Books
  • Robotics Automations Engineering Books
  • Civil Engineering Books
  • Chemical Engineering Books
  • Environmental Engineering Books
  • Electrical Engineering Books
  • Electronics Engineering Books
  • Information Technology Books
  • Software Engineering Books
  • GATE Preparation Books
  • Exciting Offers



    GATE Exam, Gate 2009, Gate Papers, Gate Preparation & Related Pages


    GATE Overview | GATE Eligibility | Structure Of GATE | GATE Training Institutes | Colleges Providing M.Tech/M.E. | GATE Score | GATE Results | PG with Scholarships | Article On GATE | GATE Forum | GATE 2009 Exclusive | GATE 2009 Syllabus | GATE Organizing Institute | Important Dates for GATE Exam | How to Apply for GATE | Discipline / Branch Codes | GATE Syllabus for Aerospace Engineering | GATE Syllabus for Agricultural Engineering | GATE Syllabus for Architecture and Planning | GATE Syllabus for Chemical Engineering | GATE Syllabus for Chemistry | GATE Syllabus for Civil Engineering | GATE Syllabus for Computer Science / IT | GATE Syllabus for Electronics and Communication Engineering | GATE Syllabus for Engineering Sciences | GATE Syllabus for Geology and Geophysics | GATE Syllabus for Instrumentation Engineering | GATE Syllabus for Life Sciences | GATE Syllabus for Mathematics | GATE Syllabus for Mechanical Engineering | GATE Syllabus for Metallurgical Engineering | GATE Syllabus for Mining Engineering | GATE Syllabus for Physics | GATE Syllabus for Production and Industrial Engineering | GATE Syllabus for Pharmaceutical Sciences | GATE Syllabus for Textile Engineering and Fibre Science | GATE Preparation | GATE Pattern | GATE Tips & Tricks | GATE Compare Evaluation | GATE Sample Papers | GATE Downloads | Experts View on GATE | CEED 2009 | CEED 2009 Exam | Eligibility for CEED Exam | Application forms of CEED Exam | Important Dates of CEED Exam | Contact Address for CEED Exam | CEED Examination Centres | CEED Sample Papers | Discuss GATE | GATE Forum of OneStopGATE.com | GATE Exam Cities | Contact Details for GATE | Bank Details for GATE | GATE Miscellaneous Info | GATE FAQs | Advertisement on GATE | Contact Us on OneStopGATE |
    Copyright © 2024. One Stop Gate.com. All rights reserved Testimonials |Link To Us |Sitemap |Privacy Policy | Terms and Conditions|About Us
    Our Portals : Academic Tutorials | Best eBooksworld | Beyond Stats | City Details | Interview Questions | India Job Forum | Excellent Mobiles | Free Bangalore | Give Me The Code | Gog Logo | Free Classifieds | Jobs Assist | Interview Questions | One Stop FAQs | One Stop GATE | One Stop GRE | One Stop IAS | One Stop MBA | One Stop SAP | One Stop Testing | Web Hosting | Quick Site Kit | Sirf Dosti | Source Codes World | Tasty Food | Tech Archive | Software Testing Interview Questions | Free Online Exams | The Galz | Top Masala | Vyom | Vyom eBooks | Vyom International | Vyom Links | Vyoms | Vyom World
    C Interview Questions | C++ Interview Questions | Send Free SMS | Placement Papers | SMS Jokes | Cool Forwards | Romantic Shayari