Rates of Change and Tangent Lines
In this section we are going to take a look at two fairly
important problems in the study of calculus. There are two reasons for looking
at these problems now.
First, both of these problems will lead us into the study
of limits, which is the topic of this chapter after all. Looking at these
problems here will allow us to start to understand just what a limit is and what
it can tell us about a function.
Secondly, the rate of change problem that we�re going to be
looking at is one of the most important concepts that we�ll encounter in the
second chapter of this course. In fact, it�s probably one of the most important
concepts that we�ll encounter in the whole course. So looking at it now will
get us to start thinking about it from the very beginning.
Tangent Lines
The first problem that we�re going to take a look at is the
tangent line problem. Before getting into this problem it would probably be
best to define a tangent line.
A tangent line to the function f(x) at the point
is
a line that just touches the graph of the function at the point in question and
is �parallel� (in some way) to the graph at that point. Take a look at the
graph below.
In this graph the line is a tangent line at the indicated
point because it just touches the graph at that point and is also �parallel� to
the graph at that point. Likewise, at the second point shown, the line does
just touch the graph at that point, but it is not �parallel� to the graph at
that point and so it�s not a tangent line to the graph at that point.
At the second point shown (the point where the line isn�t a
tangent line) we will sometimes call the line a secant line.
We�ve used the word parallel a couple of times now and we
should probably be a little careful with it. In general, we will think of a
line and a graph as being parallel at a point if they are both moving in the
same direction at that point. So, in the first point above the graph and the
line are moving in the same direction and so we will say they are parallel at
that point. At the second point, on the other hand, the line and the graph are
not moving in the same direction and so they aren�t parallel at that point.
Okay, now that we�ve gotten the definition of a tangent
line out of the way let�s move on to the tangent line problem. That�s probably
best done with an example.
Example
Find the tangent line to
at
x = 1.
Solution
We know from algebra that to find the equation of a line we
need either two points on the line or a single point on the line and the slope
of the line. Since we know that we are after a tangent line we do have a point
that is on the line. The tangent line and the graph of the function must touch
at x = 1 so the point
must
be on the line.
Now we reach the problem. This is all that we know about
the tangent line. In order to find the tangent line we need either a second
point or the slope of the tangent line. Since the only reason for needing a
second point is to allow us to find the slope of the tangent line let�s just
concentrate on seeing if we can determine the slope of the tangent line.
At this point in time all that we�re going to be able to do
is to get an estimate for the slope of the tangent line, but if we do it
correctly we should be able to get an estimate that is in fact the actual slope
of the tangent line. We�ll do this by starting with the point that we�re after,
let�s call it
.
We will then pick another point that lies on the graph of the function, let�s
call that point
.
For the sake of argument let�s take choose
and
so the second point will be
.
Below is a graph of the function, the tangent line and the secant line that
connects P and Q.
We can see from this graph that the secant and tangent
lines are somewhat similar and so the slope of the secant line should be
somewhat close to the actual slope of the tangent line. So, as an estimate of
the slope of the tangent line we can use the slope of the secant line, let�s
call it
,
which is,
Now, if we weren�t too interested in accuracy we could say
this is good enough and use this as an estimate of the slope of the tangent
line. However, we would like an estimate that is at least somewhat close the
actual value. So, to get a better estimate we can take an x that is
closer to
and
redo the work above to get a new estimate on the slope. We could then take a
third value of x even closer yet and get an even better estimate.
In other words, as we take Q closer and closer to
P the slope of the secant line connecting Q and P should be
getting closer and closer to the slope of the tangent line. If you are viewing
this on the web, the image below shows this process.
As you can see (if you�re reading this on the web) as we
moved Q in closer and closer to P the secant lines does start to
look more and more like the tangent line and so the approximate slopes (i.e.
the slopes of the secant lines) are getting closer and closer to the exact
slope. Also, do now worry about how I got the exact or approximate slopes.
We�ll be computing the approximate slopes shortly and we�ll be able to compute
the exact slope in a few sections.
In this figure we only looked at
Q�s that were to the right of
P, but we could have just as easily used
Q�s that were to the left of
P and we would have received the same
results. In fact, we should always take a look at Q�s that are on both
sides of P. In this case the same thing is happening on both sides of
P. However, we will eventually see that doesn�t have to happen. Therefore
we should always take a look at what is happening on both sides of the point in
question when doing this kind of process.
So, let�s see if we can come up with the approximate slopes
I showed above, and hence an estimation of the slope of the tangent line. In
order to simplify the process a little let�s get a formula for the slope of the
line between P and
Q,
,
that will work for any x that we choose to work with. We can get a
formula by finding the slope between P and Q using the �general�
form of
.
Now, let�s pick some values of
x getting
closer and closer to
,
plug in and get some slopes.
x |
|
x |
|
2 |
-6 |
0 |
-2 |
1.5 |
-5 |
0.5 |
-3 |
1.1 |
-4.2 |
0.9 |
-3.8 |
1.01 |
-4.02 |
0.99 |
-3.98 |
1.001 |
-4.002 |
0.999 |
-3.998 |
1.0001 |
-4.0002 |
0.9999 |
-3.9998 |
So, if we take x�s to
the right of 1 and move them in very close to 1 it appears that the slope of the
secant lines appears to be approaching -4. Likewise, if we take
x�s to the left of 1 and move them in very
close to 1 the slope of the secant lines again appears to be approaching -4.
Based on this evidence it seems that the slopes of the
secant lines are approaching -4 as we move in towards
,
so we will estimate that the slope of the tangent line is also -4. As noted
above, this is the correct value and we will be able to prove this eventually.
Now, the equation of the line that goes through
is
given by
Therefore, the equation of the tangent line to
at
x = 1 is
|