Frequency
Dependent Circuits
Why Worry
About Frequency Response?
Did you
ever buy audio equipment and look carefully at how the manufacturer specified
how well the equipment would work? (And audio equipment is one of the few
consumer items where people actually try to sell things on the basis of how well
they work!) If you looked at the specifications for audio equipment you would
probably find the following.
-
A frequency response for the
unit.
-
If the unit is a speaker set,
you'll find separate frequency responses for the different speakers like the
mid-range, or the woofer and the tweeter.
-
If the unit is a microphone,
you'll find a frequency response that tells you how the unit responds to
different frequencies.
Frequency response is an important concept in many
areas - within electrical engineering and outside of electrical engineering.
Having a good grasp of frequency response is important in many areas, so our
objectives in this lesson include the following.
An Example Circuit
We are
going to examine a simple circuit that has frequency dependent behavior, a
resistor-capacitor (RC) circuit. It is shown below. To illustrate how this
circuit responds to a sinusoidal signal input we can do any of the following.
-
We can write the differential
equation relating the input and output voltages and solve for the output
assuming a sinusoidal signal input.
-
We can assume a sinusoidal
input and use LaPlace transform methods to compute the output voltage.
-
Since the input is a sinusoid,
we know that the output contains a sinusoid and terms that decay to zero.
We can work from there.
We will
use the third approach - and we will assume a steady state output and work
backwards from the output to compute the input.
Since
the first thing we want to do is just to look at how a circuit can affect
sinsusoidal signals, we're going to assume a sinusoidal output and work
backwards to calculate the input voltage that produces that output. That's not a
very general approach, but it will get us what we want now, and prepare us for
other things to come. We will be able to do that without too much
algebraic pain, and we can learn some things from the result.
So,
we will assume that the output voltage is given by:
vout(t) =
B sin(wt)
Be sure
that you understand that B is the magnitudeof the
output signal
Now, what does that form for the output voltage imply?
vout(t)
= B sin(wt)
i(t) = Cdvout/dt
= CBwcos(wt)
vR(t)
= Ri(t) = RCB wcos(wt)
Now, we can apply KVL to get the input voltage.
vin(t)
= vR(t) +vout(t)
vin(t)
= B(RCw cos(wt)
+ sin(wt))
At this
point step back from this. It may not be obvious, but we can take advantage of a
trigonometric identity,
sin(x+y) = sin(x)cos(y) +
cos(x)sin(y)
if only we can make the things that multiply the
sines and cosines in the second bullet above look like other sines and cosines.
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